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python全局变量遇到一个问题求大神解答
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Created 2021-09-08 14:20:01  Updated 2021-09-08 15:09:44
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我发现一个问题,为什么我return一个字典全局变量,再调用时,变量会被覆盖啊,代码在下面,#号的那三行按理来说打印出来应该也是1,2,3啊,但是实际打印出来是3,3,3搞不明白。这是我回测中发现的问题,发现结果打印出来都一样,然后一步一步找发现根源出在这里。我把全局变量改成局部变量就没这问题,但我想搞明白为什么这样不行,求大佬解答。
def fun(a):
dict_zz['one'] = a
return dict_zz
def main():
params()
dict_zz_15min = fun(1)
dict_zz_1h = fun(2)
dict_zz_4h = fun(3)
print(dict_zz_15min) #
print(dict_zz_1h) #
print(dict_zz_4h) #

def params():
global dict_zz
dict_zz = {}
main()

为什么我打印出来是这个样子
{'one': 3}
{'one': 3}
{'one': 3}

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Comment
All comments (6)

    你用的同一个key,都覆盖了.你学习下python的基础

    5 years ago

    你这话有点瞧不起人了啊,什么算python基础呢?我之前在聚宽就用python写策略了....

    5 years ago

    def fun(a):

    dict_zz['one'] = a
    return dict_zz
    def main():
    params()
    dict_zz_15min = fun(1)
    print(dict_zz_15min)
    dict_zz_1h = fun(2)
    print(dict_zz_1h)
    dict_zz_4h = fun(3)
    print(dict_zz_4h) #

    def params():
    global dict_zz
    dict_zz = {}
    main()

    5 years ago

    你直接说字典是浅拷贝我就明白了......我的锅,学了这么久python这个都没搞懂

    5 years ago

    不是key的问题吧,我全局变量换成局部变量就没问题的啊,像这样key不也覆盖的吗?
    def fun(a):
    dict_zz = {}
    dict_zz['one'] = a
    return dict_zz
    def main():
    dict_zz_15min = fun(1)
    dict_zz_1h = fun(2)
    dict_zz_4h = fun(3)
    print(dict_zz_15min)
    print(dict_zz_1h)
    print(dict_zz_4h)
    main()

    5 years ago

    不是key的问题吧,我全局变量换成局部变量就没问题的啊

    5 years ago
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