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Apabila saya mengira kemiringan, ia kelihatan sangat halus di carta, tetapi dengan pengiraan koordinat, ia menghasilkan nilai yang besar kerana x terlalu kecil.
Bagaimana tuan-tuan dan puan-puan boleh menyelesaikan masalah ini?
def sudut ((v1)):
bx = 3502 -3516
by = 4
angle1 = math.atan2(bx, by)
print(angle1)
angle1 = int(angle1 * 180/math.pi)
print(angle1)
Ia adalah 14 titik, dan ia mempunyai kemiringan dan sudut yang sangat besar.
-1.2924966677897853
-74
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def 角度(v1,取长):
r = _C(exchange.GetRecords)
数据长度 = len(v1)
数据长度 = int(数据长度-1)
取长 = int(取长)
dx1 = v1[数据长度]
dy1 = 数据长度 + 1
dx2 = v1[数据长度-取长]
while dx2 is None:
取长=取长 - 1
dx2 = v1[数据长度-取长]
dy2 = 数据长度 - 取长
bx = dx1 -dx2
#by = dy1 -dy2
by = zhou*2
angle1 = math.atan2(bx, by)
angle1 = int(angle1 * 90/math.pi)
return angle1
4 years ago
- 1