ThreadCondition.notify
Wakes up one waiting thread (if any exists). Only threads that have called the wait() method can be awakened.
notify()Examples
Use the notify() function to wake up waiting threads.
javascript
function consumer(dict, condition) {
while (true) {
condition.acquire()
while (dict.get("array").length == 0) {
Log(threading.currentThread().name(), "wait()...", ", array:", dict.get("array"))
condition.wait()
}
var arr = dict.get("array")
var num = arr.shift()
Log(threading.currentThread().name(), ", num:", num, ", array:", arr, "#FF0000")
dict.set("array", arr)
Sleep(1000)
condition.release()
}
}
function main() {
var condition = threading.Condition()
var dict = threading.Dict()
dict.set("array", [])
var t1 = threading.Thread(consumer, dict, condition)
var t2 = threading.Thread(consumer, dict, condition)
var t3 = threading.Thread(consumer, dict, condition)
Sleep(1000)
var i = 0
while (true) {
condition.acquire()
var msg = ""
var arr = dict.get("array")
var randomNum = Math.floor(Math.random() * 5) + 1
if (arr.length >= 3) {
condition.notifyAll()
msg = "notifyAll"
} else {
arr.push(i)
dict.set("array", arr)
if (randomNum > 3 && arr.length > 0) {
condition.notify()
msg = "notify"
} else {
msg = "pass"
}
i++
}
Log(_D(), "randomNum:", randomNum, ", array:", arr, ", msg:", msg)
condition.release()
Sleep(1000)
}
}See Also
Remarks
The notify() function wakes up one thread in the waiting queue.
When the notify() function wakes up a thread, that thread will reacquire the thread lock.