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This is the first time that the project has been funded by the European Commission.

Author: 1070278998@qq.com, Created: 2021-12-20 15:47:42, Updated:

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The Little DreamHello, you can send to the crowdfunding area, where many developers can be contacted.

The Little DreamThe full test, the article, is available in the library. I don't know if it's written or not, you can test it. I implemented it using this Fischer conversion algorithm.

smarioThe dream god is very efficient.

The Little DreamWhat's up? function getHighest ((arr, period) { if (arr.length == 0 ◄ arr.length - period < 0) { return null is I'm not sure. var beginIndex = arr.length - period var ret = arr [beginIndex].High for (var i = 0 ; i < arr.length - 1 ; i++) { if (arr[i + 1].High > ret) { ret = arr[i + 1].High I'm not sure. I'm not sure. return ret I'm not sure. function getLowest ((arr, period) { if (arr.length == 0 ◄ arr.length - period < 0) { return null is I'm not sure. var beginIndex = arr.length - period var ret = arr[beginIndex].Low is the lowest value for (var i = 0 ; i < arr.length - 1 ; i++) { if (arr[i + 1].Low < ret) { ret = arr[i + 1].Low I'm not sure. I'm not sure. return ret I'm not sure. function calcFisher ((records, ratio, period) { var preFish = 0 var before X = 0 var arrFish = [] // when the length of the K line is not enough to satisfy the cycle if (records.length < period) { for (var i = 0 ; i < records.length ; i++) { ArrFish.push ((0) I'm not sure. return arrFish I'm not sure. // across the K line for (var i = 0 ; i < records.length ; i++) { var fish = 0 var x is equal to 0. var bar = records[i] var mid = (bar.High + bar.Low) divided by 2 // The current BAR is not enough to compute the period If (i < period - 1) { fish = 0 preFish = 0 arrFish.push ((fish)) Continue I'm not sure. // the highest and lowest price in the calculation cycle var bars = [] for (var j = 0 ; j <= i ; j++) { bars.push ((records[j]) I'm not sure. var lowestLow = getLowest (bars, period) var highestHigh = getHighest ((bars, period) What do you think? // the price parameter x = ratio * 2 * ((mid - lowestLow) / (highestHigh - lowestLow) - 0.5) + (1 - ratio) * preX If (x > 0.99) x is equal to 0.999. } else if (x < -0.99) { x is equal to -0.999. I'm not sure. PreX is equal to x. fish = 0.5 * Math.log (((1 + x) / (1 - x)) + 0.5 * preFish preFish = fish arrFish.push ((fish)) I'm not sure. return arrFish I'm not sure. What's up?

The Little Dream X.X！

1070278998@qq.comThis is the first time I've seen this feature on my computer. This is the first time I have seen this kind of thing. Don't waste your time. Do it now.

The Little DreamWell, take some time to research.

1070278998@qq.comDid you officially add this indicator? Is there a timetable?